IN

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Description

An IN condition tests a value for membership in a set of values or in a subquery. (Redshift SQL Language Reference IN condition)

Grammar Syntax

expression [ NOT ] IN (expr_list | table_subquery)

This function is fully supported by Snowflake.

Sample Source Patterns

Setup Table

Redshift

CREATE TABLE sales (
    id INTEGER IDENTITY(1,1),
    price FLOAT,
    saleDate DATE
);

INSERT INTO sales (price, saleDate) VALUES
(5000, '12/19/2024'),
(4000, '12/18/2024'),
(2000, '12/17/2024'),
(1000, '11/11/2024'),
(7000, '10/10/2024'),
(7000, '05/12/2024');

CREATE TABLE InTest (
col1 Varchar(20) COLLATE CASE_INSENSITIVE,
col2 Varchar(30) COLLATE CASE_SENSITIVE,
d1 date,
num integer,
idx integer);

INSERT INTO InTest values ('A', 'A', ('2012-03-02'), 4,6);
INSERT INTO InTest values ('a', 'a', ('2014-01-02'), 41,7);

Snowflake

Input Code:

Redshift

IN -> Redshift_01.sql

SELECT * FROM sales
WHERE id IN (2,3);

SELECT 5 IN (
SELECT id FROM sales
WHERE price = 7000
) AS ValidId;

select t.col1 in ('a ','b','c') as r1, t.col2 in ('a ','b','c') as r2 from InTest t order by t.idx;

Results

Output Code:

Snowflake

OUT -> Redshift_01.sql

SELECT * FROM
    sales
WHERE id IN (2,3);

SELECT 5 IN (
SELECT id FROM
 sales
WHERE price = 7000
) AS ValidId;

select t.col1 in (RTRIM('a '), RTRIM('b'), RTRIM('c')) as r1, t.col2 in (RTRIM('a '), RTRIM('b'), RTRIM('c')) as r2 from
InTest t order by t.idx;

Results

Related EWIs

No related EWIs.

Known Issues

No issues were found.