SPRKPY1031
pyspark.sql.column.Column.contains has a workaround
This issue appears when the tool detects the usage of pyspark.sql.column.Column.contains which has a workaround.
Input code:
booleanColumn = df.col.contains('o')
Output code:
#EWI: SPRKPY1030 => pyspark.sql.column.Column.contains has a workaround, see documentation for more info
booleanColumn = df.col.contains('o')
Column.contains(self, item: Any)
Action: use the 'contains' function from 'snowflake.snowpark.functions', and add the column as the first parameter.
from snowflake.snowpark import functions as f
booleanColumn = f.contains(df.col, 'o')
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Last modified 21d ago