SPRKSCL1125

org.apache.spark.sql.functions.count

This issue code is deprecated since Spark Conversion Core 2.9.0

Message: org.apache.spark.sql.functions.count has a workaround, see documentation for more info

Category: Warning

Description

This issue appears when the SMA detects a use of the org.apache.spark.sql.functions.count function, which has a workaround.

Scenario

Input

Below is an example of the org.apache.spark.sql.functions.count function, first used with a column name as an argument and then with a column object.

val df = Seq(
  ("Alice", "Math"),
  ("Bob", "Science"),
  ("Alice", "Science"),
  ("Bob", null)
).toDF("name", "subject")

val result1 = df.groupBy("name").agg(count("subject").as("subject_count"))
val result2 = df.groupBy("name").agg(count(col("subject")).as("subject_count"))

Output

The SMA adds the EWI SPRKSCL1125 to the output code to let you know that this function is not fully supported by Snowpark, but it has a workaround.

val df = Seq(
  ("Alice", "Math"),
  ("Bob", "Science"),
  ("Alice", "Science"),
  ("Bob", null)
).toDF("name", "subject")

/*EWI: SPRKSCL1125 => org.apache.spark.sql.functions.count has a workaround, see documentation for more info*/
val result1 = df.groupBy("name").agg(count("subject").as("subject_count"))
/*EWI: SPRKSCL1125 => org.apache.spark.sql.functions.count has a workaround, see documentation for more info*/
val result2 = df.groupBy("name").agg(count(col("subject")).as("subject_count"))

Recommended fix

Snowpark has an equivalent count function that receives a column object as an argument. For that reason, the Spark overload that receives a column object as an argument is directly supported by Snowpark and does not require any changes.

For the overload that receives a string argument, you can convert the string into a column object using the com.snowflake.snowpark.functions.col function as a workaround.

val df = Seq(
  ("Alice", "Math"),
  ("Bob", "Science"),
  ("Alice", "Science"),
  ("Bob", null)
).toDF("name", "subject")

val result1 = df.groupBy("name").agg(count(col("subject")).as("subject_count"))
val result2 = df.groupBy("name").agg(count(col("subject")).as("subject_count"))

Additional recommendations

• For more support, you can email us at [e-mail] or post an issue in the SMA.