SPRKPY1036

pyspark.sql.column.Column.getField

This issue code has been deprecated

Message: pyspark.sql.column.Column.getField has a workaround, see documentation for more info

Category: Warning

Description

This issue appears when the SMA detects a use of the pyspark.sql.column.Column.getField function, which has a workaround.

Scenario

Input

Below is an example of a use of the pyspark.sql.column.Column.getField function that generates this EWI. In this example, the getField function is used to extract the name from the info column.

df = spark.createDataFrame([(1, {"name": "John", "age": 30}), (2, {"name": "Jane", "age": 25})], ["id", "info"])
df_with_name = df.withColumn("name", col("info").getField("name"))

Output

The SMA adds the EWI SPRKPY1036 to the output code to let you know that this function is not directly supported by Snowpark, but it has a workaround.

df = spark.createDataFrame([(1, {"name": "John", "age": 30}), (2, {"name": "Jane", "age": 25})], ["id", "info"])
#EWI: SPRKPY1036 => pyspark.sql.column.Column.getField has a workaround, see documentation for more info
df_with_name = df.withColumn("name", col("info").getField("name"))

Recommended fix

As a workaround, you can use the Snowpark column indexer operator with the name of the field as the index.

df = spark.createDataFrame([(1, {"name": "John", "age": 30}), (2, {"name": "Jane", "age": 25})], ["id", "info"])
df_with_name = df.withColumn("name", col("info")["name"])

Additional recommendations

• For more support, you can email us at [e-mail] or post an issue in the SMA.