SPRKPY1018
pyspark.sql.functions.date_sub
Description
Scenario
col = df.select(date_sub(df.colName, 5))#EWI: SPRKPY1018 => pyspark.sql.functions.date_sub has a workaround, see documentation for more info
col = df.select(date_sub(df.colName, 5))from pyspark.sql.functions import date_sub
df.withColumn("date", date_sub(df.colName, 5))Additional recommendation
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