SPRKPY1020

pyspark.sql.functions.instr

Message: pyspark.sql.functions.instr has a workaround

Category: Warning.

Description

This issue appears when the tool detects the usage of pyspark.sql.functions.instr which has a workaround.

Scenario

Input

Here is a basic example of usage of pyspark instr:

from pyspark.sql import SparkSession
from pyspark.sql.functions import instr
spark = SparkSession.builder.getOrCreate()
df = spark.createDataFrame([('abcd',)], ['test',])
df.select(instr(df.test, 'cd').alias('result')).collect()

Output:

SMA returns the EWI SPRKPY1020 over the line where instr is used, so you can use to identify where to fix.

from snowflake.snowpark import Session

spark = Session.builder.getOrCreate()
spark.update_query_tag({"origin":"sf_sit","name":"sma","version":{"major":0,"minor":0,"patch":0},"attributes":{"language":"Python"}})
df = spark.createDataFrame([('abcd',)], ['test',])
#EWI: SPRKPY1020 => pyspark.sql.functions.instr has a workaround, see documentation for more info
df.select(instr(df.test, 'cd').alias('result')).collect()

Recommended fix

Requires a manual change by using the function charindex and changing the order of the first two parameters.

import snowflake.snowpark as snowpark
from snowflake.snowpark import Session
from snowflake.snowpark.functions import charindex, lit

spark = Session.builder.getOrCreate()
spark.update_query_tag({"origin":"sf_sit","name":"sma","version":{"major":0,"minor":0,"patch":0},"attributes":{"language":"Python"}})
df = spark.createDataFrame([('abcd',)], ['test',])
df.select(charindex(lit('cd'), df.test).as_('result')).show()

Additional recommendation

• For more support, you can email us at [e-mail] or post an issue in the SMA.